How many starting positions Fischer random with only bishop rule, no castling.
I know like it's between 960 and 8!/8 but what's the exact amount.
Edit: I tried and got
16*15*6*2*1= 2880
4 possible squares for a light-squared bishop
4 possible squares for a dark-squared bishop
6 possible squares for a queen (two squares are already occupied by the bishops)
5 possible squares for a rook
4 possible squares for another rook
3 possible squares for a king
2 possible squares for the knights
4x4x6x5x4x3x2 = 11 520
@Krtekcze Umm, that's more than 8!/8 = 5040
yeah, I suppose we need to divide a final result by 2 for rooks and 2 for knights, then it would be 2 880
Would be interesting to check engine evaluation for all 2 880 starting positions, I believe, many positions would be a dead loss from the very beginning for black.
